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Simplest Form Of Iron Ore

Feb 15, 2011 If the iron ore is 73% Fe2O3, then from a 1000 g sample of the ore you will have 730 g of Fe2O3. moles of Fe = 730 g Fe2O3[(1 mole)/(159.69 g/mol)](2 moles Fe)/(1 mole Fe2O3) = 4.57 moles Fe. mass Fe = 4.57 moles Fe(55.845 g)/(1 mol) = 255 g Fe. Hope this is helpful.

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